java.getFilePathOfCurrentFile

//Möglichkeit 1
Test test = new Test();
System.out.println(getClassResource(Test.class));
//Möglichkeit 2
Class<?> c = Test.class;
String path = c.getResource(c.getSimpleName() + ".class").getPath().replace(c.getSimpleName() + ".class", "");
System.out.println(path);
//Möglichkeit 3
Path workingDirectory= Paths.get("").toAbsolutePath();
System.out.println(workingDirectory);
//Möglichkeit 4
String workingDir = System.getProperty("user.dir");
System.out.println("Current working directory : " + workingDir);
private static String getCurrentFilePathSourceFile() {
Class<?> c = this.getClass();
String path = c.getResource(c.getSimpleName() + ".class").getPath().replace(c.getSimpleName() + ".class", "");
Path workingDirectory= Paths.get("").toAbsolutePath();
String pathArray[]=workingDirectory.toString().split("\\\\");
String workingPackage=pathArray[pathArray.length-1];
path= path.replace("out/production/"+workingPackage,"src");
return path;
}
public String getClassFilePath() throws URISyntaxException {
URL url=this.getClass().getResource(".");
File file= new File(url.toURI());
return file.getPath();
}